36x^2-480x-2465=0

Solution for 36x^2-480x-2465=0 equation:

36x^2-480x-2465=0

a = 36; b = -480; c = -2465;
Δ = b2-4ac
Δ = -4802-4·36·(-2465)
Δ = 585360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{585360}=\sqrt{144*4065}=\sqrt{144}*\sqrt{4065}=12\sqrt{4065}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-480)-12\sqrt{4065}}{2*36}=\frac{480-12\sqrt{4065}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-480)+12\sqrt{4065}}{2*36}=\frac{480+12\sqrt{4065}}{72}
$